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Madhyamik Mathematics Suggestion – Similarity সদৃশ্যতা Chapter 18 | WBBSE Class 10

15 Sept 2026 0 views
Madhyamik Mathematics | সদৃশ্যতা অধ্যায় ১৮
Similarity is an important geometry topic where students need to understand proportional sides, equal corresponding angles and parallel-line relationships.

Madhyamik Mathematics Suggestion – Similarity focuses on selected questions from সদৃশ্যতা বা Similarity, Chapter 18. The chapter includes objective questions, True or False statements, fill-in-the-blanks, short-answer problems and 5-mark descriptive questions.

This rewritten guide presents the same source-supported question areas in a cleaner and more student-friendly format so that Class 10 students can use it for focused revision.

01 MCQ Practice
02 Concept Revision
05 Marks Long Questions

Similarity Chapter 18 – Important Question Areas

The suggested questions mainly test the basic ideas of similar triangles, proportional division, parallel lines, trapezium properties and relationships between corresponding sides and angles.

Question Type Marks Main Focus
Multiple Choice Questions 1 Similarity and proportionality
True or False 1 Basic properties of similar figures
Fill in the Blanks 1 Definitions and standard properties
Short Answer 2 Reasoning and application
Long Answer 5 Geometrical proof

Multiple Choice Questions | MCQ

Question 1

In ΔABC, BC is parallel to PQ. If AD = QC, AB = 12 cm and AQ = 2 cm, find the value of CQ.

A. 4 cm
B. 5 cm
C. 6 cm
D. 8 cm
Answer: 4 cm

Question 2

A line parallel to MN in ΔLMN meets LM and LN at P and O respectively. If PM = LQ, LP = 9 cm and QN = 4 cm, find PM.

A. 5 cm
B. 6 cm
C. 8 cm
D. 9 cm
Answer: 6 cm

Question 3

A line parallel to BC in ΔABC intersects AB and AC at P and Q respectively. If AP = 3.2 cm, AQ = 2.2 cm and QC = 2.2 cm, find the length of AB.

A. 6 cm
B. 7 cm
C. 8 cm
D. 8.6 cm
Answer: 8 cm

Question 4

A line parallel to BC in ΔABC intersects AB and AC at D and E respectively. If AD = x + 2, DB = 2x + 9, AE = x and EC = 2x + 3, find x.

A. 1
B. 2
C. 3
D. 4
Answer: x = 3

Question 5

In trapezium ABCD, AD is parallel to BC. A line parallel to BC meets AB and DC at P and Q. If AP : PB = 2 : 1, determine DQ : QC.

A. 2 : 3
B. 3 : 2
C. 1 : 2
D. 2 : 1
Answer: DQ : QC = 2 : 1

True or False | সত্য অথবা মিথ্যা

These statements are useful for quickly revising the fundamental properties of similarity.

1. Two congruent triangles are always similar.True
2. All rectangles are similar.False
3. If two triangles are similar, they must be congruent.False
4. All circles are congruent.False
5. A square and a rhombus are always similar.False
6. All rhombuses are similar.False
7. All equilateral triangles are similar.True

Fill in the Blanks | শূন্যস্থান পূরণ

1. All squares are similar.
2. All circles are similar.
3. All equilateral triangles are always similar.
4. If a straight line divides two sides of a triangle proportionally, it has a parallel relationship with the third side.
5. A line parallel to the parallel sides of a trapezium divides the other two sides proportionally.
6. If the corresponding sides of two triangles are proportional, the triangles are called similar.

Short Answer Questions | 2 Marks

Question 1 — Similar Triangles and Parallel Lines

If the given intersecting-line configuration forms similar triangles ΔACE and ΔBDE, show the parallel-line relationship indicated by the geometry.

Solution approach:

From the similarity of ΔACE and ΔBDE, the corresponding angles are equal. Therefore, the relevant pairs of alternate angles are equal. Equal alternate angles establish a parallel relationship between the corresponding lines.

ΔACE ∼ ΔBDE → Corresponding angles are equal → Parallel lines
Notation note: The source question and its printed solution contain an inconsistency in the line labels. The solution refers to AC and BD, while the question text refers to AB and CD. The explanation above follows the similarity argument and parallel-line principle actually used in the source.

Question 2 — Rectangle and Square

Will a rectangle measuring 4 cm × 5 cm be similar to a square whose side is 3 cm. Give a reason.

Answer:

No. Although the corresponding angles of both figures are right angles, their corresponding side ratios are not equal. Therefore, the rectangle and the square are not similar.

Question 3 — Comparing Two Passport-Size Photographs

Are a passport-size photograph taken ten years ago and a current passport-size photograph necessarily similar. Give a reason.

Answer:

No. The two photographs may have the same stated size but their shapes may be different. Similarity depends on the preservation of shape and proportional dimensions, not merely on having the same nominal size.

Long Answer Questions | 5 Marks

Question 1 — Intersecting Chord and Diameter

A circle has AB as its diameter. PQ is a chord perpendicular to AB, and AB and PQ intersect at R. Prove that:

AR × BR = PR × QR
A B P Q R
Schematic construction showing AB as the diameter and PQ perpendicular to AB at R.

Proof

Join AP and BP.
Since AB is the diameter, the angle subtended by AB at P is a right angle. The perpendicular construction also gives the corresponding right-angle relationship at R.
Using the relevant angle relationships, ΔAPR and ΔBQR are similar triangles.
From similarity, corresponding sides are proportional.
Therefore, AR / PR = QR / BR.
Cross multiplication gives AR × BR = PR × QR.
Therefore, AR × BR = PR × QR

Question 2 — Perpendicular from a Point on a Circle

In a circle with centre O, AB is a diameter. From a point P on the circle, a perpendicular is drawn to AB and meets AB at N. Prove the corresponding product relationship given by the similarity of the two right triangles.

PB² = AB × BN
A B P N O
Schematic figure for the diameter AB and perpendicular PN meeting AB at N.

Proof

AB is the diameter of the circle, so the angle APB is a right angle.
Since PN is perpendicular to AB, the angle PNB is also a right angle.
The two relevant right triangles are therefore similar through their corresponding acute angles.
Using the corresponding sides of the similar triangles gives the required proportional relation.
On simplification, PB / BN = AB / PB.
Cross multiplication gives PB² = AB × BN.
Therefore, PB² = AB × BN
Source notation note: The question text in the source prints the final product using BD in one place, while the diagram and solution image use BN. The rewritten proof follows the diagram-supported notation, namely BN.

Important Similarity Concepts for Quick Revision

Concept Key Point
Similar Triangles Corresponding angles are equal and corresponding sides are proportional.
Congruent Triangles Congruent figures have the same shape and the same size.
Equilateral Triangles All equilateral triangles are similar because their corresponding angles are equal.
Squares All squares have the same shape, so they are similar.
Circles All circles have the same shape, although their sizes may differ.
Parallel-Line Division A line parallel to one side of a triangle produces proportional division of the other two sides.
Trapezium A line parallel to the parallel sides divides the other two sides proportionally.

How to Prepare Similarity Questions

Identify the given geometry first. Mark the parallel lines, equal angles, perpendicular lines and corresponding sides before beginning the proof.
Look for similar triangles. Most proof-based problems in this section become easier once the correct pair of similar triangles is identified.
Write the correspondence carefully. Keep the order of corresponding vertices consistent when writing a similarity statement.
Use proportional sides. After proving similarity, use the corresponding-side ratio to obtain the required result.
Finish with a clear conclusion. Write the final relation separately so that the examiner can easily identify the required result.

Quick Revision Table

Section What to Revise Priority
MCQ Proportional division and similarity-based calculations High
True or False Difference between similarity and congruence High
Fill in the Blanks Standard similarity properties High
Short Answer Reasoning using angles, side ratios and shape High
5-Mark Problems Similar triangles and geometrical proof Very High

Final Revision Note

For Madhyamik Mathematics Chapter 18 – Similarity, students should give special attention to proportional sides, corresponding angles, similar triangles and parallel-line constructions. The objective questions are useful for quick revision, while the descriptive problems require a proper sequence of geometrical reasoning.

Before writing a proof, identify the triangles involved, establish their similarity and then use the resulting proportional relationship. This approach makes the longer questions more systematic and easier to present in the examination.

Explore More Madhyamik Mathematics Resources

For broader Class 10 revision, you can also explore the Cademy Madhyamik suggestion resource covering Mathematics and other WBBSE subjects.

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Madhyamik Mathematics Similarity সদৃশ্যতা Chapter 18 WBBSE Class 10 Mathematics Suggestion

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